| kimclps |
2013-01-17 21:00 |
(1) 總長67mm，倍率-8，以薄透鏡求解，焦距=67/(2+8+0.125)=6.617mm P[-E@0h)-t
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(2) 物距=6.617*1.125=7.44mm<10mm，像距=6.617*9=59.55mm>33mm @7c?xQVd$
所以需為telephoto型式(+ -) \7eUw,~Q>
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(3) 再設+ 透鏡焦距為f1，- 透鏡焦距為f2，兩鏡片間隔為d=67-33-10=24 .sW|Id )
以(1/f1)+(1/f2)-d/(f1*f2)=1/6.617 及 (1-d*(1/f1))*6.617 =33 k'Hs}z
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