Under POP propagation you will see Beam Definition, under this tab you can define either the "Total Power" of the beam or the "Peak Irradiance". So the total power returns under the window (as you captured) will be reporting the total power with respect to the energy defined under this "Beam Definition". -GJ~xcf0
諸葛隨風(fēng)
2016-07-21 09:49
hopebox:Under POP propagation you will see Beam Definition, under this tab you can define either the "Total Power" of the beam or the "Peak Irradiance". So the total power returns under the window (as you captured) will be reporting the total power .. (2016-07-20 16:07) y/i{6P2`,D
|?A:[C#X 選擇total power 和 peak irradiance會有什么不同呢，還有我想改變鏡子大小來看光的通過率，設(shè)定選擇surface type里的 aperture type 里的通光孔徑的大小，再看total power 的大小，這樣是不是可以說明不同半徑下光的通過率啊。
hopebox
2016-07-21 15:47
諸葛隨風(fēng):選擇total power 和 peak irradiance會有什么不同呢，還有我想改變鏡子大小來看光的通過率，設(shè)定選擇surface type里的 aperture type 里的通光孔徑的大小，再看total power 的大小，這樣是不是可以說明不同半徑下光的通過率啊。 (2016-07-21 09:49) qP {Fwn
bT7+$^NHf Whether choosing Total power or peak irradance, the energy/power of beam as a function of radius will just be calculated relatively to how you define it. So it shouldn't matter, and just depends on how the source beam is defined though (since the beam profile is there). A=W:}szt] f f&jR71E I think the method you proposed shall return the physical quantity you want to study. Hope this helps.
諸葛隨風(fēng)
2016-07-22 13:26
hopebox:Whether choosing Total power or peak irradance, the energy/power of beam as a function of radius will just be calculated relatively to how you define it. So it shouldn't matter, and just depends on how the source beam is defined though (since the beam pro .. (2016-07-21 15:47) EXMW,
F53
.g/[ Yes, Alien21 is right, you could check Polarization > Transmission as a way to check it, too. pdm(7^ Xq
)7Im}? If using POP, make sure you tick the box of "Use Polarization". So the total power shall account all sorts of energy loss.
光潤
2016-07-26 17:12
謝謝樓主
愛因斯譚
2016-07-27 10:16
學(xué)習(xí)一下 G62;p #
thorn12345
2017-10-20 10:25
hopebox:Yes, Alien21 is right, you could check Polarization > Transmission as a way to check it, too. :Cezk
