目前是對(duì)于變焦目鏡的不理解，請(qǐng)各位大俠指點(diǎn)指點(diǎn)，我是菜鳥，所以問的問題都很淺顯。    ,#%SK;1<  
一個(gè)初始結(jié)構(gòu)例子：變焦距虛焦面目鏡， G4yUC<TqBP  
E.F.L=10~20   B.F.L=-14.53~-6.33  Φ出/2=1.2～2.3  F.A.=±25°~±18° <t6d)mJ%  
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序號(hào)         r                       d                 n                           ν Wy)('EM  
1            47.3                  1.76             1.7552              27.5 wrK#lh2  
2           15.5                    6.22             1.64                 60.1 kt<@H11  
3            -23.105               ***1 7S2c|U4IM  
4             25.7                    3.26           1.60311            60.7 l   4H7Oh*P\j  
5             -900.522             0.2   Qrz*Lvle h  
6            40.95                   4.69             1.72916          54.7    7+S44)w}~  
7              -20                     1.23              1.80518          25.4 ZX]
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8              -287.692           ***2      ZW2s[p r  
9               -52                     1.23               1.51633          64.1   ^=#!D[xj>  
10            31.034  O<iI  
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問題是，   "sIN86pCs  
1.從這樣的數(shù)據(jù)中，能得到什么信息輸入到ZEMAX中 (\q[gyR  
2.B.F.L是后截距，有什么用？    ;Yu
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3.Φ出/2是什么意思？能作為什么輸入到ZEMAX中？ <